The infinite continued fraction representation of √5 is [2,4,4,4,4,...]. Give the first four decimal estimates of √5 coming from the partial convergents of this continued fraction. (Round each to 6 decimal places.)
Given, infinite continued fraction representation of sqrt(5) is [2,4,4,4,4,...], i.e., a0=2, a1=4, a2=4, a3=4, a4=4
The partial convergents of our continued fraction repr. Of sqrt(5) are, say: P0, P1, P2, P3, P4
P0=a0 = 2
P1= = 2+(1/4) = 2.25
P2= = 2+(1/(4+(1/4))) = 2+(1/4.25) = 2+0.235294118 = 2.235294118 = 2.235294 (Round to 6 decimal places)
P3= =2+(1/(4+(1/4+(1/4))))=2+(1/(4+0.235294118)) = 2+0.236111111 = 2.236111111 = 2.236111 (Round to 6 decimal places)
P4 = = 2+(1/(4+(1/4+(1/(4+(1/4))))))
= 2+(1/(4+0.236111111)) = 2+0.236065574 = 2.236065574 = 2.236066 (Round to 6 decimal places)
Similarly,
P5= 2.236068111 = 2.236068 (Round to 6 decimal places)
P6= 2.23606797 = 2.236068 (Round to 6 decimal places)
Hence, approximation of = 2.236068
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