Let f : R → R + be defined by the formula f(x) = 10^2−x . Show that f is injective and surjective, and find the formula for f −1 (x).
Suppose f : A → B and g : B → A. Prove that if f is injective and f ◦ g = iB, then g = f −1 .
2. f(x) = 102-x
So, f(x) = f(y) implies, 102-x = 102-y
So, 2 - x = 2 - y
So, x = y
Hence, f is injective.
Also, let, y belongs to the co-domain R+, so, y > 0.
Then, f(x) = y implies, 102-x = y
So, 2 - x = log10 y. (Since, y > 0)
So, x = 2 - log10 y belongs to R, such that, f(x) = y
So, f is surjective.
&, f -1(x) = 2 - log10 x
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