Question

Derive or prove the three point backward difference approximation of the first derivative, aka Dh--f, of...

Derive or prove the three point backward difference approximation of the first derivative, aka Dh--f, of a function f(x), using either polynomial interpolant method (Newton's or Lagrange's) here is the first derivative approximation: f'(x) = (3* f(x) - 4*f(x-h)+ f(x-2h)) /2h , which is congruent to Dh--f

Homework Answers

Answer #1

Doubt in this then comment below..i will explain you..

.

Please thumbs up for this solution..thanks..

.

here i use langrange interpolation

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h^2 )...
Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h^2 ) to estimate the first and second derivatives of f(x)= 0.4x^5 ‐0.2x^3 +6x^2 ‐13 at x=2 using a step size h=1. Repeat the computation using h values of 0.5, 0.25, and 0.1. Compare your results with the exact derivative value at x=2.
For a given h, a derivative at a point x0 can be approximated using a forward...
For a given h, a derivative at a point x0 can be approximated using a forward difference, a backward difference, and a central difference: f 0 (x0) ≈ f(x0 + h) − f(x0) h forward difference f 0 (x0) ≈ f(x0) − f(x0 − h) h backward difference f 0 (x0) ≈ f(x0 + h) − f(x0 − h) 2h central difference. Using MATLAB or Octave, Write a script that prompts the user for an h value and an x0...
Using the central divided difference approximation with a step size of 0.4, the derivative of f(x)...
Using the central divided difference approximation with a step size of 0.4, the derivative of f(x) = 6x^4 at x = 2.1 is ____. Keep 4 decimal places.
1)         Prove (with an ε- δ proof) limx→22x3-x2-3x=6 2)         fx= x5-5x3       a)   Find the first derivative....
1)         Prove (with an ε- δ proof) limx→22x3-x2-3x=6 2)         fx= x5-5x3       a)   Find the first derivative. b)   Find all critical numbers. c)   Make a single line graph showing where the function is increasing and where it is decreasing. d) Find the coordinates of all stationary points, maxima, and minima. e)   Find the second derivative. Find any numbers where the concavity of the function may change. f) Make a single line graph showing the concavity of the function. Find the coordinates...
1) Derive the quotient rule ( f g ) ′ = (f ′ ⋅ g −...
1) Derive the quotient rule ( f g ) ′ = (f ′ ⋅ g − f ⋅ g ′ )/g 2 using the product rule and the chain rule. I was able to get this with product rule(i think) but unsure how to use chain rule 2) Identify a rate of accumulation (or decay) in your life that changes over time. Be creative. a) Describe it in a sentence or two: the rate of accumulation of pages read this...
1.The first-order derivative of a function of the form y=f(x) evaluated at x=2 is: a. The...
1.The first-order derivative of a function of the form y=f(x) evaluated at x=2 is: a. The rate of change [Delta_y/Delta_x], where Delta_x=3-2 and Delta_y=f(3)-f(2). b. The slope of the line that is tangent to y=f(x) at the point (2,f(2)) in the (x,y) Cartesian space. c. The slope of the line that is tangent to y=f’(x) at the point (2,f’(2)) in the (x,y’) Cartesian space. d. None of the above. 2.A university hires you to advise them on how to maximise...
​​​​​​ Below are ten functions. Find the first derivative of each. All of the derivatives can...
​​​​​​ Below are ten functions. Find the first derivative of each. All of the derivatives can be found by using combinations of the constant rule, power function rule and sum-difference rule.   Do not use the product rule. It is not needed. The degree of difficulty (more or less) increases from (a) to (j). Be sure to show intermediate work. Five points are awarded for correctly developed derivatives. There is no partial credit, because an incorrect derivative is useless. For example,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT