Question

what is the coefficient of x^4Y^6 In the expansion of (2x-y^2)^7

what is the coefficient of x^4Y^6 In the expansion of (2x-y^2)^7

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

To solve this problem apply binomial theorem.

Since,

The coefficient of x^4 *y^6 is,

The coefficient of x^4 *y^6 in (2x-y^2)^7 is -560.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use Gaussian Elimination to solve and show all steps: 1. (x+4y=6) (1/2x+1/3y=1/2) 2. (x-2y+3z=7) (-3x+y+2z=-5) (2x+2y+z=3)
Use Gaussian Elimination to solve and show all steps: 1. (x+4y=6) (1/2x+1/3y=1/2) 2. (x-2y+3z=7) (-3x+y+2z=-5) (2x+2y+z=3)
find dy/dx a. (x+y)^4 =4y-9x b. y= (x +6)^2x c. y= cos^-1 (3x^2 -5x +1 )
find dy/dx a. (x+y)^4 =4y-9x b. y= (x +6)^2x c. y= cos^-1 (3x^2 -5x +1 )
Solve by matrix method x-y+2z=7 3x+4y-5z=-5 2x-y+3z=12
Solve by matrix method x-y+2z=7 3x+4y-5z=-5 2x-y+3z=12
Solve the following differential equations using inspection: 1) y”+4y=12 2) y””+4y”+4y=-20 3) (D^4 -4D^2)y=24 4) y”-y=x-1...
Solve the following differential equations using inspection: 1) y”+4y=12 2) y””+4y”+4y=-20 3) (D^4 -4D^2)y=24 4) y”-y=x-1 5) D(D-3)y=4 6) (D^2+2D-8)(D+3)y=0 7) y”-y’-2y=18xe^(2x)
solve the given DE equation y''-4y'+20y= (x+1)e^2x cos x + 2x^2 e^2x sinx
solve the given DE equation y''-4y'+20y= (x+1)e^2x cos x + 2x^2 e^2x sinx
(differential equations): solve for x(t) and y(t) 2x' + x - (5y' +4y)=0 3x'-2x-(4y'-y)=0 note: Prime...
(differential equations): solve for x(t) and y(t) 2x' + x - (5y' +4y)=0 3x'-2x-(4y'-y)=0 note: Prime denotes d/dt
Solve for undetermined coefficients: y'''-y''-4y'+4y=5 - e^x +e^2x
Solve for undetermined coefficients: y'''-y''-4y'+4y=5 - e^x +e^2x
Q1) (a) What is the distance of a point (x,y) to the line −2x+4y=−16? The solution...
Q1) (a) What is the distance of a point (x,y) to the line −2x+4y=−16? The solution should be a function of x and y. (b) The set of points equidistant from the lines −2x+4y=−16 and 5x−4y=28 forms two lines. Give implicit equations for these two lines.
Find the method by the Variation of Parameters y'' - 4y' +4y = (e^(2x))/x
Find the method by the Variation of Parameters y'' - 4y' +4y = (e^(2x))/x
Q1) (a) What is the distance of a point (x,y) to the line −2x+4y=−16? The solution...
Q1) (a) What is the distance of a point (x,y) to the line −2x+4y=−16? The solution should be a function of x and y. (b) The set of points equidistant from the lines −2x+4y=−16 and 5x−4y=28 forms two lines. Give implicit equations for these two lines. Please show clear working
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT