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Given the second order initial value problem y′′+y′−6y=5δ(t−2),  y(0)=−5,  y′(0)=5 Y(s) denote the Laplace transform of y. Then...

Given the second order initial value problem y′′+y′−6y=5δ(t−2),  y(0)=−5,  y′(0)=5

Y(s) denote the Laplace transform of y. Then

Y(s)=

Taking the inverse Laplace transform we obtain

y(t)=

y(t)=

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