Question

y'' +3y= t

y'(0)=0

y'(pi) = 0

solve with fourier series

Answer #1

Solve the following wave equation using Fourier Series
a2uxx = utt, 0 < x < pi,
t > 0, u(0,t) = 0 = u(pi,t), u(x,0) = sinxcosx,
ut(x,0) = x(pi - x)

Solve the following wave equation using Fourier Series
a2uxx = utt, 0 < x < pi,
t > 0, u(0,t) = 0 = u(pi,t), u(x,0) = sin2x - sin3x,
ut(x,0) = 0

f(t) is defined on (-pi,pi] as
t^3 Extend periodically and compute the fourier series.

solve y''-3y'+2y=0 using power series please

Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0)
y(0)=0,y''(0)=0

Find the Fourier series of the function:
f(x) =
{0, -pi < x < 0
{1, 0 <= x < pi

Solve the ODE
y"+3y'+2y=(e^-t)(sin2t) when y'(0)=y(0)=0

Solve y'-3y=2e^t y(0)=e^3-e using Laplace transform.

(PDE
Use the method of separation of variables and Fourier series to
solve where m is a real constant
And boundary value prob. Of Klein Gordon eqtn.
Given :
Utt - C^2 Uxx + m^2 U = 0 ,for 0 less than x less pi , t greater
than 0
U (0,t) = u (pi,t) =0 for t greater than 0
U (x,0) = f (x) , Ut (x,0)= g (x) for 0 less than x less than
pj

Use Laplace transforms to solve 3y ′′ − 48y = δ(t − 2), y(0) =
1, y ′ (0) = −4.

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