Sol.-
According to the question
x= 2(3+y) x= 6+2y. ---------(1)
and
x+y=126 -------(2)
Substituting the value of x from eq.(1) into eq.(2) we get
(6+2y)+y=126
6+3y=126
3y=126-6
3y=120
y=120/3
y= 40
substituting in eq.(1) we get
x=6+2×40=6+80
x=86
Hence, x=86 and y=40
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