Question

Now, velocity, v = u + at

x-axis → VxA = axAxt = VxA = 4.33 t → ①

so, by y-axis → VyA = -2.5 t →②

Position formula, s = ut + ½ at²

by x-axis, xA = ½ × 4.33 t² → xA = 2.165t² →③

so, by y-axis, yA = -1.25 t² →④

Velocity → x-axis, VxB = 0 +0*t

                              VxB = 0 →⑤

Velocity → y-axis, VyB = Uy - 10 t →⑥

Position → x-axis, xB = 8.66 + 0*t

                              xB = 8.66 m →⑦

Position → y-axis, yB = 5Uyt - 5t²→⑧

Sketch position and velocity time graphs for ball “A” and “B” using the same chart.

Can anyone help me draw these 2 graph？ I don’t know if I draw them correctly

Answer 1

For Position time graph of A

The (x,y) cordinate is (2.165t²,-1.25t²)

now we will plot the graph for different values of t

with time as x-axis and position as y-axis

t	0	1	2	3
x	0	2.165	8.66	19.485
y	0	-1.25	-5	-11.25

The graph will be

For Velocity time graph of A

The (x,y) cordinate is (4.33t,-2.5t)

now we will plot the graph for different values of t

with time as x-axis and Velocity as y-axis

t	0	1	2	3
x	0	4.33	8.66	12.99
y	0	-2.5	-5	-7.5

The graph will be

Similarly we will graw for ball B.