Question

A random sample of 200 automobile owners in a region shows that an automobile is driven...

A random sample of 200 automobile owners in a region shows that an automobile is driven on average 22 comma 500 kilometers per year with a standard deviation of 3700 kilometers. Assume the distribution of measurements to be approximately normal. ​(a) Construct a 90​% confidence interval for the average number of kilometers an automobile is driven annually in the region. ​(b) What can we assert with 90​% confidence about the possible size of our error if we estimate the average number of kilometers driven by car owners in the region to be 22 comma 500 kilometers per​ year?

Homework Answers

Answer #1

Plz don't forget to Like

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To...
It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly selected automobile owners are asked to keep a record of the kilometers they travel. Would you agree with this claim if the random sample showed an average of 23,500 kilometers and a standard deviation of 3900 kilometers? Use a P-value in your conclusion. but construct a 99% confidence interval
Suppose that a study shows that an electric bike is driven 23,500 km/year on average and...
Suppose that a study shows that an electric bike is driven 23,500 km/year on average and has a standard deviation of 3900 km. Assume that the measurements’ distribution is approximately normal. a) Calculate the 3rd quartile. b) Solve for the probability that a randomly selected electric bike is driven between 10,000 and 20,000 km per year.
A sample of 25 two-year old chickens shows that they lay an average of 21 eggs...
A sample of 25 two-year old chickens shows that they lay an average of 21 eggs per month.  the standard deviation of the sample was 2 eggs.  Find the 90% confidence interval of the true mean. For a group of 10 men subjected to a stress situation, the mean number of heartbeats per minute was 126, and the standard deviation was 4.  Find the 95% confidence interval of the true mean.
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the...
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the standard normal ? values with the corresponding ? values if you were forming the following confidence intervals. (a)    90% confidence interval z= t= (b)    95% confidence interval z=   t= (c)    98% confidence interval ?= t= 2) A confidence interval for a population mean has length 20. a) Determine the margin of error. b) If the sample mean is 58.6, obtain the confidence interval. Confidence interval: ( ,...
1. Is it true that the sample mean is always equal to the population mean that...
1. Is it true that the sample mean is always equal to the population mean that we picked the sample from? Explain. 2. Is it true that the confidence interval is narrower for 95% confidence than for 90% confidence? Explain 3. Is it true that the Sample means are less variable than individual observations as n→∞ ? Explain 4. A newspaper article reports that the average income of Canadian adults is 45000 with a 90% confidence interval of 28000 to...
1.The following data shows test scores for a sample of statistics students. 83, 64, 84, 76,...
1.The following data shows test scores for a sample of statistics students. 83, 64, 84, 76, 84, 54, 75, 59, 70, 63, 80, 84, 73, 68, 52, 65, 90, 52, 95, 36, 78, 61, 59, 84, 95, 47, 87 a. Find a 95% confidence interval for the mean test score for all students. b. Interpret this 95% CI for the population mean. c. What is the margin of error? 2. A recent national survey found that high school students watched...
1. Canadians are becoming more conscious of the importance of good nutrition, and some researchers believe...
1. Canadians are becoming more conscious of the importance of good nutrition, and some researchers believe that we may be altering our diets to include less red meat and more fruits and vegetables. To test this theory, a researcher decides to select hospital nutritional records for subjects surveyed 10 years ago and to compare the average amount of beef consumed per year to the amounts consumed by an equal number of subjects she will interview this year. She knows that...
(1 point) Weights of 10 red and 36 brown randomly chosen M{\&}M plain candies are listed...
(1 point) Weights of 10 red and 36 brown randomly chosen M{\&}M plain candies are listed below. Red: 0.9080.9090.9070.920.9360.8980.8980.8740.9130.9240.9080.9070.9360.8980.9130.9090.920.8980.8740.924 Brown: 0.9090.9150.9550.9140.9310.9090.9050.930.8570.8770.9660.9020.920.9040.8660.8710.8720.9280.9880.920.8580.8980.9360.9210.9850.8750.9290.90.9230.8610.8670.8760.9020.8970.9180.9130.9090.9050.920.9880.9850.8670.9150.930.9040.920.8750.8760.9550.8570.8660.8580.9290.9020.9140.8770.8710.8980.90.8970.9310.9660.8720.9360.9230.9180.9090.9020.9280.9210.8610.913 1.    To construct a 95% confidence interval for the mean weight of red M{\&}M plain candies, you have to use A. The t distribution with 11 degrees of freedom B. The normal distribution C. The t distribution with 9 degrees of freedom D. The t distribution with 10 degrees of freedom E. None of the above 2.    A 95% confidence interval...
The Federal Election Commission collects information about campaign contributions and disbursements for candidates and political committees...
The Federal Election Commission collects information about campaign contributions and disbursements for candidates and political committees each election cycle. During the 2012 campaign season, there were 1,619 candidates for the House of Representatives across the United States who received contributions from individuals. The table below shows the total receipts from individuals for a random selection of 40 House candidates rounded to the nearest $100. $3,600 $1,243,900 $10,900 $385,200 $581,500 $7,400 $2,900 $400 $3,714,500 $632,500 $391,000 $467,400 $56,800 $5,800 $405,200 $733,200...
In a study of academic procrastination, it was determined that for a random sample of 18...
In a study of academic procrastination, it was determined that for a random sample of 18 undergrad students at a mid-size public university, the mean time spent studying for the final exam in an intro statistics course was 7.74 hours with a standard deviation of 3.40 hours. What is the point estimate of the mean final exam study time for all undergrad students? In a study of academic procrastination, it was determined that for a random sample of 18 undergrad...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT