Question

Discuss the convergence From infinity to n=1 1/n^3*sin^2*n

Discuss the convergence From infinity to n=1 1/n^3*sin^2*n

Homework Answers

Answer #1

Here I'm using caparison test and p test for series is convergence or divergences .Here given series is convergence by p test which stated below .Answer is below thank you.

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