Question

y" +2y' +y = 6 sin t - 4cost, y(0) = -1, y(0) = 1

y" +2y' +y = 6 sin t - 4cost, y(0) = -1, y(0) = 1

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
y''(t) + 3y'(t) + 2y(t) = 0 if t < π 10 , sin(t) if t...
y''(t) + 3y'(t) + 2y(t) = 0 if t < π 10 , sin(t) if t ≥ π , subject to y(0) = 5, y'(0) = 2
Use Laplace to solve y" + 2y' + 2y = e-t, y(0) = 0, y'(0) =...
Use Laplace to solve y" + 2y' + 2y = e-t, y(0) = 0, y'(0) = 1
Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0) y(0)=0,y''(0)=0
Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0) y(0)=0,y''(0)=0
y''(t) + 2y'(t) + 3y(t) = 1 y(0) = 1 y'(0) = -1 a)homogenous solution? b)particular...
y''(t) + 2y'(t) + 3y(t) = 1 y(0) = 1 y'(0) = -1 a)homogenous solution? b)particular solution? c)overall solution?
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the differential equation with initial value y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the differential equation with initial value y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
(x+1)y'=y-1 2) dx+(x/y+(e)?)dy=0 3)ty'+2y=sint 4) y"-4y=-3x²e3x 5) y"-y-2y=1/sinx 6)2x2y"+xy'-2y=0 ea)y=x' b) x=0 2dx/dt-2dy/dt-3x=t; 2
(x+1)y'=y-1 2) dx+(x/y+(e)?)dy=0 3)ty'+2y=sint 4) y"-4y=-3x²e3x 5) y"-y-2y=1/sinx 6)2x2y"+xy'-2y=0 ea)y=x' b) x=0 2dx/dt-2dy/dt-3x=t; 2
y''+4y=sint + u_pi(t)sin(t-pi) y(0)=1 y'(0)=0 find the solution
y''+4y=sint + u_pi(t)sin(t-pi) y(0)=1 y'(0)=0 find the solution
Use the Laplace transform to solve the following IVP y′′ +2y′ +2y=δ(t−5) ,y(0)=1,y′(0)=2, where δ(t) is...
Use the Laplace transform to solve the following IVP y′′ +2y′ +2y=δ(t−5) ,y(0)=1,y′(0)=2, where δ(t) is the Dirac delta function.
Determine the type of below equations and solve it. a-)(sin(xy)+xycos(xy)+2x)dx+(x2cos(xy)+2y)dy=0 b-)(t-a)(t-b)y’-(y-c)=0     a,b,c are constant.
Determine the type of below equations and solve it. a-)(sin(xy)+xycos(xy)+2x)dx+(x2cos(xy)+2y)dy=0 b-)(t-a)(t-b)y’-(y-c)=0     a,b,c are constant.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT