(i)
n = 55
= 5.28
s = 0.55
SE = s/
= 0.55/
= 0.0742
= 0.01
ndf = n - 1 = 55 - 1 = 54
From Table, critical values of t = 2.6700
Confidence Interval:
5.28 (2.6700 X 0.0742)
= 5.28 0.1980
= ( 5.0820 ,5.4780)
Confidence Interval:
5.0820 < < 5.4780
(ii)
Since not all the values of the Confidence Interval 5.0820 < < 5.4780 are less than 5.37, we conclude that the sample is not from a population with mean less than 5.37.
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