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The number of defects in 12 different production runs were 2, 5, 10, 0, 5, 3,...

The number of defects in 12 different production runs were 2, 5, 10, 0, 5, 3, 4, 3, 2, 2, 0 and 0. This data can be summarized in a frequency distribution as follows a. The values that occur in the set in increasing order are 0, 2, 3, 4, 5 and 10. b. The frequency of 0 is 3 since it occurs 3 times in the set. The frequency of 2 is 3 since it occurs 3 times in the set. The frequency of 3 is 2 since it occurs twice in the set. The frequency of 5 is 2 since it occurs twice in the set. Both 4 and 10 have frequency 1 since they occur only once in the set. c. So, the set can be summarized in a table: Measurement Frequency 0 ? 2 ? 3 ? 4 ? 5 ? 10 ? Notice that the frequencies add up to 12, which is the number of measurements in the set. Calculations are easier if the data are given in a frequency distribution. I) Find the frequency, arithmetic mean, median, and mode of the set of defects in the 12 production runs. II) Calculate the standard deviation of the set of defects in the 12 production runs. d. Each defect in a production run means that a box that contains 6 bottles must be discarded. For the production runs given earlier, find the mean, median, mode, range and standard deviation of the number of bottles discarded.

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Answer #1

And new Mode is 0 and 12 . Since they ocuur maximum no of times

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