Question

Expand in Fourier Series.

f(x) = (sinx)^3, -pi < x < pi

Answer #1

Expand the Fourier Series.
f(x) = 1- x, -pi < x < pi

Calculate the Fourier Series S(x) of f(x) = sin(x/2), -pi < x
< pi. What is S(pi) = ?

Find the Fourier series of the function:
f(x) =
{0, -pi < x < 0
{1, 0 <= x < pi

Expand the Fourier Series.
f(x) = x|x|, -L < x < L, L > 0

f(t) is defined on (-pi,pi] as
t^3 Extend periodically and compute the fourier series.

Expand the function f(x) = x^2 in a Fourier sine series on the
interval 0 ≤ x ≤ 1.

Expand the following periodic functions in the interval –pi
< x < pi in a sine Cosine Fourier Series
1. F (x) = 0 -pi < x < pi/2
= 1 Pi/2 < x <pi
2. F(x) = 0 -pi <x < pi
= x 0 < x < pi

Find the Taylor series for f(x)= sinx at a=pi/6. (Find up to the
fifth degree)

Find the real Fourier series of the piece-wise defined
function
f(x) = Pi+x -2<=x<2

f(x) = 2x - 7
x ∈ (0,7)
Draw a plot of the periodic Fourier Series expansion of f(x).
What is its value at x=0 and why? Is it odd or even?
Expand the given function in a Fourier Series also

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