Question

Find the general solution using Variation of Parameters.

y''-y'-2y=2e^(2t)

Answer #1

Find a solution to y^''-4y^'-5y=2e^2t using variation of
parameters.

Find a solution to y^''-4y^'-5y=2e^2t using variation of
parameters. Find the solution to the differential equation in
problem 6, this time using the method of undetermined
coefficients.

Using variation of parameters, find a particular solution of the
given differential equations:
a.) 2y" + 3y' - 2y = 25e-2t (answer should be: y(t) =
2e-2t (2e5/2 t - 5t - 2)
b.) y" - 2y' + 2y = 6 (answer should be: y = 3 + (-3cos(t) +
3sin(t))et )

find the general solution to y"-2y'+y=x-1ex (variation of
parameters

a) Find the general solution of the differential equation
y''-2y'+y=0
b) Use the method of variation of parameters to find the general
solution of the differential equation y''-2y'+y=2e^t/t^3

Find the general solution to the differential equation y′′+ 2y′=
3 + 4 sin 2t.(Hint: Variation of parameters requires integration by
parts, so undetermined coefficientsis recommended—however, be
careful.)

Find the general solution to the following differential equation
using the method of variation of parameters.
y"-2y'+2y=ex csc(x)

Find the general solution using variation of
parameters.
y"+10y'+25y=50

x'= y + 1/sint,
y'= -x,
Find a general solution of system using variation of
parameters

Find a particular solution for the differential equation by
variation of parameters.
y''- y' -2y = e^3x , y(0) = -3/4 , y'(0)=15/4

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