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By using delta- epsilon show that the two definitions of the limit are equivalent Def1: lim┬(x→x_0...

By using delta- epsilon show that the two definitions of the limit are equivalent

Def1: lim┬(x→x_0 )⁡〖f(x)=f(x_0)〗. If for any ϵ>0,there exist a δ>0 such that 0<|x-x_0 |<δ implies |f(x)-L|<ϵ

Def2: If for any sequence {x_n }→x_0 we have f(x_n)→L

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