Use the Differential of Transforms Theorem (Theorem 2 in section 7.4) to find the inverse Laplace transform of F(s) = ln((s+2)/(s-2)) + ln((s+3)/(s-3)).
According to the differential of transform theorem,
L {-t.f(t)} = F'(s)
So, L-1 {F'(s)} = -t.f(t)
Therefore the inverse Laplace transform of F(s) is equal to
f(t) = (e-2t +e-3t -e2t -e3t )/t
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