Question

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 207.9-cm and a standard
deviation of 1.5-cm. For shipment, 26 steel rods are bundled
together.

Find*P*_{26},
which is the average length separating the smallest 26% bundles
from the largest 74% bundles.

Find

Answer #1

= 207.9

= 1.5

n = 26

SE = /

= 1.5/

=0.2942

26% corresponds to area = 0.50 - 0.26 = 0.24

Table of Area Under Standard Normal Curve gives Z = - 0.645

So,

Z = - 0.645 = ( - 207.9)/0.2942

So,

= 207.9 - (0.645 X 0.2942)

= 207.7102

So,

Answer is:

**207.7102**

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 225.1-cm and a standard
deviation of 1.3-cm. For shipment, 10 steel rods are bundled
together. Find P95, which is the average length separating the
smallest 95% bundles from the largest 5% bundles. P95 = _____-cm
Enter your answer as a number accurate to 2 decimal place.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 197.5-cm and a standard
deviation of 2-cm. For shipment, 6 steel rods are bundled
together.
Find P11, which is the average length separating the smallest
11% bundles from the largest 89% bundles.
P11 =______________ -cm
Enter your answer as a number accurate to 2 decimal place.
Answers obtained using exact z-scores or z-scores rounded to 3
decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 179.5-cm and a standard
deviation of 0.7-cm. For shipment, 20 steel rods are bundled
together.
Find P95, which is the average length
separating the smallest 95% bundles from the largest 5%
bundles.
P95 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 216.5-cm and a standard
deviation of 2.3-cm. For shipment, 24 steel rods are bundled
together.
Find P15, which is the average length
separating the smallest 15% bundles from the largest 85%
bundles.
P15 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 252.7-cm and a standard
deviation of 2.4-cm. For shipment, 9 steel rods are bundled
together.
Find P82, which is the average length
separating the smallest 82% bundles from the largest 18%
bundles.
P82 = -cm
Enter your answer as a number accurate to 2 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 91.1-cm and a standard
deviation of 0.5-cm. For shipment, 25 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is greater than 90.8-cm.
P(M > 90.8-cm) =

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 226.6-cm and a standard
deviation of 1.7-cm. For shipment, 10 steel rods are bundled
together. Find the probability that the average length of a
randomly selected bundle of steel rods is less than 227.9-cm. P(M
< 227.9-cm) =

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 211.4-cm and a standard
deviation of 1.3-cm. For shipment, 5 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is greater than 211.5-cm.
P(M > 211.5-cm) =

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 129.2-cm and a standard
deviation of 0.5-cm. For shipment, 27 steel rods are bundled
together. Find the probability that the average length of a
randomly selected bundle of steel rods is greater than 129.3-cm.
P(M > 129.3-cm) = __________

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 245.7-cm and a standard
deviation of 1.8-cm. For shipment, 5 steel rods are bundled
together. Find the probability that the average length of a
randomly selected bundle of steel rods is between 245.1-cm and
248.2-cm.
P(245.1-cm < M < 248.2-cm) =

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 7 minutes ago

asked 16 minutes ago

asked 32 minutes ago

asked 53 minutes ago

asked 53 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago