Question

Solution.The Fibonacci numbers are defined by the recurrence relation is defined F1 = 1, F2 =...

Solution.The Fibonacci numbers are defined by the recurrence relation is defined F1 = 1, F2 = 1 and for n > 1, Fn+1 = Fn + Fn−1. So the first few Fibonacci Numbers are: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, . . . There are numerous curious properties of the Fibonacci Numbers Use the method of mathematical induction to verify a: For all integers n > 1 and m > 0 Fn−1Fm + FnFm+1 = Fn+m. Solution. (Hint: use induction with respect to m. First verify the formula for m = 1 case (here use again induction on n) then assume that it is true for m = 1, m = 2, · · · , m = k case and prove that it remains true if m = k + 1 (with the use of induction on n) b: What one can obtain from formula a) after substitution n = m + 1 Solution. c) Use the principle of Mathematical Induction to prove that for n 3 − n is multiple of 3 for all positive integers n.

Homework Answers

Answer #1

in part c I have shown that n^3-n is divisible by 3 for all n ,natural numbers .So n^3-n is multiple of 3.

Any doubt ask in comment .

Upvote it

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Fibonacci Numbers. The Fibonacci numbers are 1,1,2,3,5,8,13,21,….1,1,2,3,5,8,13,21,…. We can define them inductively by f1=1,f1=1, f2=1,f2=1, and...
Fibonacci Numbers. The Fibonacci numbers are 1,1,2,3,5,8,13,21,….1,1,2,3,5,8,13,21,…. We can define them inductively by f1=1,f1=1, f2=1,f2=1, and fn+2=fn+1+fnfn+2=fn+1+fn for n∈N. Prove that fn=[(1+√5)n−(1−√5)n]/2n√5.
The Fibonacci numbers are defined recursively as follows: f0 = 0, f1 = 1 and fn...
The Fibonacci numbers are defined recursively as follows: f0 = 0, f1 = 1 and fn = fn−1 + fn−2 for all n ≥ 2. Prove that for all non-negative integers n: fn*fn+2 = ((fn+1))^ 2 − (−1)^n
The Fibonacci series can be defined recursively as: F1 = 0; F2 = 1; and Fn...
The Fibonacci series can be defined recursively as: F1 = 0; F2 = 1; and Fn = Fn-2 + Fn-1. Show inductively that: (F1)2 + (F2)2 + ... + (Fn)2 = (Fn)(Fn+1).
Recall that the Fibonacci numbers are defined by F0 = 0,F1 = 1 and Fn+2 =...
Recall that the Fibonacci numbers are defined by F0 = 0,F1 = 1 and Fn+2 = Fn+1 + Fn for all n ∈N∪{0}. (1) Make and prove an (if and only if) conjecture about which Fibonacci numbers are multiples of 3. (2) Make a conjecture about which Fibonacci numbers are multiples of 2020. (You do not need to prove your conjecture.) How many base cases would a proof by induction of your conjecture require?
In mathematics, the Fibonacci numbers are the numbers in the following integer sequence, called the Fibonacci...
In mathematics, the Fibonacci numbers are the numbers in the following integer sequence, called the Fibonacci sequence, and characterized by the fact that every number after the first two is the sum of the two preceding ones: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, … The sequence Fn of Fibonacci numbers is defined by the recurrence relation: Fn = Fn-1 + Fn with seed values F1 = 1 F2 = 1 For more information on...
Prove the following identities. (a) F1 +F3 +F5 +...+F2n−1 = F2n. (b) F0 −F1 +F2 −F3...
Prove the following identities. (a) F1 +F3 +F5 +...+F2n−1 = F2n. (b) F0 −F1 +F2 −F3 +...−F2n−1 +F2n = F2n−1 −1. (c) F02 +F12 +F2 +...+Fn2 = Fn ·Fn+1. (d) Fn−1Fn+1 − Fn2 = (−1)n. Discrete math about Fibonacci numbers
The Fibonacci sequence is defined as follows F0 = 0 and F1 = 1 with Fn...
The Fibonacci sequence is defined as follows F0 = 0 and F1 = 1 with Fn = Fn−1 +Fn−2 for n > 1. Give the first five terms F0 − F4 of the sequence. Then show how to find Fn in constant space Θ(1) and O(n) time. Justify your claims
Using mathematical induction, prove the following result for the Fibonacci numbers: f_1+f_3+⋯+f_2n-1=f_2n
Using mathematical induction, prove the following result for the Fibonacci numbers: f_1+f_3+⋯+f_2n-1=f_2n
The Fibonacci numbers Fsub n are defined by Fsub1=1, Fsub2=1 and for n>1, Fsub n+1=Fsubn+Fsubn-1. Use...
The Fibonacci numbers Fsub n are defined by Fsub1=1, Fsub2=1 and for n>1, Fsub n+1=Fsubn+Fsubn-1. Use PMI to prove that for all natural numbers "n" F^2 sub1+F^2sub2 + ...+F^2subn=Fsubn times Fsub n+1
Assume S is a recursivey defined set, defined by the following properties: 1 ∈ S n...
Assume S is a recursivey defined set, defined by the following properties: 1 ∈ S n ∈ S ---> 2n ∈ S n ∈ S ---> 7n ∈ S Use structural induction to prove that all members of S are numbers of the form 2^a7^b, with a and b being non-negative integers. Your proof must be concise. Remember to avoid the following common mistakes on structural induction proofs: -trying to force structural Induction into linear Induction. the inductive step is...