60 kg female, RER=0.74, eats 1900 calories a day, VO2= 3.6ml/Kg/min.
VO2=x ml/min/60 kg=3.6ml/Kg/min,
x ml/min=216ml/min=0.216L/min.
VO2=0.216L/min.
she eats 1900 calories and we know that 5000 calories= 1L of O2.
1900 calories=1900/5000L=0.38L
RER=0.74
therefore,RER in calories =(0.74*4.92) /0.90 = 4.04 kcal
Vo2 in cal = 5.23cal
therefore RMR= 1900+5.23+4=1900.23cal
DEE for moderately active =1900.23*1.55=2945.35
for a 60 kg woman the DEE is high so she has to lose weight
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