Question

Find y as a function of x if y(4)−6y‴+9y″=0, y(0)=12, y′(0)=18, y″(0)=9, y‴(0)=0. y(x)=?

Find y as a function of x if y(4)−6y‴+9y″=0,

y(0)=12, y′(0)=18, y″(0)=9, y‴(0)=0.

y(x)=?

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve the initial-value problem. y"-6y'+9y=0; y(0)=2, y'(0)=3 Given that y1=x2 is a solution to y"+(1/x) y'-(4/x2)...
Solve the initial-value problem. y"-6y'+9y=0; y(0)=2, y'(0)=3 Given that y1=x2 is a solution to y"+(1/x) y'-(4/x2) y=0, find a second, linearly independent solution y2. Find the Laplace transform. L{t2 * tet} Thanks for solving!
Find the general solution of the equation: y''+6y'+9y=0 where y(1)=3 y' (1)=-2 and then find the...
Find the general solution of the equation: y''+6y'+9y=0 where y(1)=3 y' (1)=-2 and then find the particular solution.
Find y as a function of t if y′′+6y′+10y=0 y(0)=7, y′(0)=4 y(t)=
Find y as a function of t if y′′+6y′+10y=0 y(0)=7, y′(0)=4 y(t)=
Consider the second-order homogeneous linear equation y''−6y'+9y=0. (a) Use the substitution y=e^(rt) to attempt to find...
Consider the second-order homogeneous linear equation y''−6y'+9y=0. (a) Use the substitution y=e^(rt) to attempt to find two linearly independent solutions to the given equation. (b) Explain why your work in (a) only results in one linearly independent solution, y1(t). (c) Verify by direct substitution that y2=te^(3t) is a solution to y''−6y'+9y=0. Explain why this function is linearly independent from y1 found in (a). (d) State the general solution to the given equation
Solve the given initial-value problem. y''' + 6y'' + 9y' = 0,  y(0) = 0, y'(0) =...
Solve the given initial-value problem. y''' + 6y'' + 9y' = 0,  y(0) = 0, y'(0) = 1, y''(0) = −6
Question : y''+6y'+9y=0,y(0)=2,y'(0)=1 , 4y''+12y'+9y=0,y(0)=2,y'(0)=2 y''-y'-2y=cosx , y''+3y'+2y=x^2 - e^2x , y''-3y'+2y=sinx  , y''-2y'-3y=3e^2x
Question : y''+6y'+9y=0,y(0)=2,y'(0)=1 , 4y''+12y'+9y=0,y(0)=2,y'(0)=2 y''-y'-2y=cosx , y''+3y'+2y=x^2 - e^2x , y''-3y'+2y=sinx  , y''-2y'-3y=3e^2x
Find the general solution to y''+6y'+9y=e^-3x
Find the general solution to y''+6y'+9y=e^-3x
Solve the initial value problem y′′+6y′+9y=0, y(−1)=3, y′(−1)=3.
Solve the initial value problem y′′+6y′+9y=0, y(−1)=3, y′(−1)=3.
Find y as a function of t if 9y′′−42y′+130y=0, y(0)=7,y′(0)=5. y(t)=
Find y as a function of t if 9y′′−42y′+130y=0, y(0)=7,y′(0)=5. y(t)=
y”+6y’+9y=e^-3t
y”+6y’+9y=e^-3t
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT