Question

How can I prove that any node of a binary search tree of n nodes can be made the root in at most n − 1 rotations?

Answer #1

1. Assume the key of the right child below the root node of a
binary search tree is 40. The value in the root node could be
________.
2. On average, searching for an item in a balanced binary search
tree is _________ operation.
3. Where is the inorder successor of a node A in a binary search
tree?

A binary tree isfullif every non-leaf node has exactly two
children. For context, recallthat we saw in lecture that a binary
tree of heighthcan have at most 2h+1−1 nodes, and thatit achieves
this maximum if it iscomplete, meaning that it is full and all
leaves are at the samedistance from the root. Findμ(h),
theminimumnumber of nodes that a full tree of heighthcan have, and
prove your answer using ordinary induction onh. Note that tree of
height of 0 isa single...

(TCO 6) In the following binary tree, the root node is
_____.
24
32
17
37
(TCO 6) In the following binary tree, the height of the node
with value 39 is _____.
Group of answer choices
1
2
3
4
(TCO 6) In a binary search tree, the key in the _____ node is
larger than the key in the root node.
Group of answer choices
right
left
root
header

In this lab, you will write a program that creates a binary
search tree based on user input. Then, the user will indicate what
order to print the values in. **Please write in C code**
Start with the bst.h and bst.c base code provided to you. You
will need to modify the source and header file to complete this
lab.
bst.h:
#ifndef BST_H
#define BST_H
typedef struct BSTNode
{
int value;
struct BSTNode* left;
struct BSTNode* right;
} BSTNode;
BSTNode*...

Here is a picture of a Binary Search Tree.
First, construct the Binary Search Tree using the following
BinaryNode as we discussed in class.
public class BinaryNode {
private int value;
private BinaryNode leftChild;
private BinaryNode rightChild;
public BinaryNode(int value) {
this.value = value;
leftChild = null;
rightChild = null;
}
public BinaryNode(int value, BinaryNode leftChild, BinaryNode rightChild)
{
this.value = value;
this.leftChild = leftChild;
this.rightChild = rightChild;
}
public int getValue() {
return value;
}
public void setValue(int value)...

Write a routine to list out the nodes of a binary tree in
level-order. List the root, then nodes at depth 1, followed by
nodes at depth 2, and so on. You must do this in linear time. Prove
your time bound (Java)

1. a) Suppose that a binary tree of height h has n nodes. Show
that h ≥ log2 (n+2) - 1.
b) Using the formula in part (a) find the minimum height if a
binary tree with 1000 nodes.
c) What is the maximum possible height of a binary tree with
1000 nodes?

what is the common between binary search tree and B tree? Can
all the binary search tree be considered a special case of some
vaild B tree why or why not?

Binary Search Tree with multiple structs?
Hi, I am having an issue with trying to create a binary search
tree while having multiple structs. The struct code provided is
provided for us.
#define CAT_NAME_LEN 25
#define APP_NAME_LEN 50
#define VERSION_LEN 10
#define UNIT_SIZE 3
struct app_info{
char category[CAT_NAME_LEN]; // name of category
char app_name[APP_NAME_LEN]; // name of application
char version[VERSION_LEN]; // version number
float size; // size of application
char units[UNIT_SIZE]; // GB or MB
float price; // price in...

Construct a Binary Search Tree using the following
data: (5 pts)
54
37
47
28
44
71
40
60
(Make sure to show dummy nodes)
b) Illustrate how will you search for V = 39 from the
above tree and how many searches will be needed. (5
pts)
c) Illustrate how you will delete the root from the
above tree, redraw the tree after deletion. (5 pts). Redraw the
tree.

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 15 minutes ago

asked 44 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago