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What is the radius (in inches) of the base of a cone that will have the...

What is the radius (in inches) of the base of a cone that will have the smallest possible surface area for a volume of 12.7 oz.? Vcone = 1/3πr2h SAcone = πr(r2+h2)1/2 + πr2 1 oz = 1.80468751 in3 Check your formulas with these values: for r=2 in and h=4 in, V=16.755 in3 and SA=40.666 in2

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