Using Chinese Remainder Theorem solve for X:
x = 2 (mod 3)
x = 4 (mod 5)
x = 5 (mod 8)
I have the answer the professor gave me, but I can`t understand what`s going on. So if you could please go over the answer and explain, it would help a lot.
x = 2 (mod 3)
x = 3a + 2
3a + 2 = 4 (mod 5)
(2) 3a = 2 (2) (mod 5) -----> why number 2?
a= 4 (mod 5) ---------> What happened with 6?
a = 5b + 4
x = 3 (5b + 4) + 2 --------> what`s going on here?
x = 15 b + 14
15b + 14 = 5 (mod 8)
7b + 6 = 5 (mod 8)
7b = -1 (mod 8)
(7) 7b = 7 (mod 8) (7)
b = 1 (mod 8)
b = 8c + 1
x = 15 (8c + 1) + 14
x + 120c + 29
x = 29 (mod 120)
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