PLEASE DON'T USE ANY OTHER PROOFS FROM POOFS BY CASES! USE DEFINITION OF ABSOLUTE VALUE!
And I was thinking of doing 4 cases:
1. x greater than or equal to 0, and y greater than or equal to 0
2. x greater than or equal to 0, y less than 0
3. x less than 0, y greater than or equal to 0
4. x less than 0 , and y is less than 0.
Proofs by cases - absolute value.
Prove each statement
(d)
For real numbers x and y, |x+y|≤|x|+|y|.
You can use the fact proven in the previous problem that for any real number z, z≤|z| and −z≤|z|.
Other way
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