Consider a manufacturing cell in company ABC that repairs defective computers. Computers arrive to the cell and wait in a single queue to be processed on a first-come-first-serve basis by one repair operator who can only work on one computer at a time. Assume that the simulation begins at time 0 with a computer (Computer #1) already being processed (scheduled to be complete in 30 minutes) and another computer (computer #2) waiting in the queue (with a process time of 80 minutes). The time between the arrival of subsequent computers to the cell and their process time is as follows:
Minutes until Next Arrival |
Required Minutes of Processing Time |
|
Computer #3 |
120 |
130 |
Computer #4 |
60 |
55 |
Computer #5 |
45 |
110 |
Computer #6 |
190 |
30 |
Computer #7 |
160 |
15 |
Computer #8 |
45 |
80 |
Computer #9 |
90 |
60 |
Computer #10 |
70 |
100 |
For example, computer #3 will arrive at time 120 and require 130 minutes of service. Computer #4 will arrive at time 180 (120+60) and require 55 minutes of service.
Construct a simulation table and perform a simulation for completing the processing of all ten computers. The objective of the simulation is to determine the following statistics:
1) Average time for a computer in queue =
time at which service of previous computer is completed - time at which current computer arrives
2) Average time a computer is in the cell = Average waiting time of computer in queue + processing time of it
3) Average number of computers in the system is 1
4) Utilization of cell operator = = 700 / 880 = 0.7954 or 79.54%
Computer number |
Time at which computer arrives in queue |
Time at which operator takes computer for repair |
Average time of computer in queue | Average time of computer in cell |
1 | 0 | 0 | 0 | 30 |
2 | 0 | 30 | 30 | 110 |
3 | 120 | 120 | 0 | 130 |
4 | 180 | 250 | 70 | 125 |
5 | 225 | 305 | 80 | 190 |
6 | 415 | 415 | 0 | 30 |
7 | 575 | 575 | 0 | 15 |
8 | 620 | 620 | 0 | 80 |
9 | 710 | 710 | 0 | 60 |
10 | 780 | 780 | 0 | 100 |
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