Question

Given that the gcd(a, m) =1 and gcd(b, m) = 1. Prove that gcd(ab, m) =1

Given that the gcd(a, m) =1 and gcd(b, m) = 1. Prove that gcd(ab, m) =1
Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

gcd is greatest common divisor

So gcd of two or more integers is the largest positive integer that divide each of the integer

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
prove that if gcd(a,b)=1 then gcd (a-b,a+b,ab)=1
prove that if gcd(a,b)=1 then gcd (a-b,a+b,ab)=1
4. Let a, b, c be integers. (a) Prove if gcd(ab, c) = 1, then gcd(a,...
4. Let a, b, c be integers. (a) Prove if gcd(ab, c) = 1, then gcd(a, c) = 1 and gcd(b, c) = 1. (Hint: use the GCD characterization theorem.) (b) Prove if gcd(a, c) = 1 and gcd(b, c) = 1, then gcd(ab, c) = 1. (Hint: you can use the GCD characterization theorem again but you may need to multiply equations.) (c) You have now proved that “gcd(a, c) = 1 and gcd(b, c) = 1 if and...
Prove that if a|n and b|n and gcd(a,b) = 1 then ab|n.
Prove that if a|n and b|n and gcd(a,b) = 1 then ab|n.
Prove that for positive integers a and b, gcd(a,b)lcm(a,b) = ab. There are nice proofs that...
Prove that for positive integers a and b, gcd(a,b)lcm(a,b) = ab. There are nice proofs that do not use the prime factorizations of a and b.
Prove that if gcd(a,b)=1 and c|(a+b), then gcd(a,c)=gcd(b,c)=1.
Prove that if gcd(a,b)=1 and c|(a+b), then gcd(a,c)=gcd(b,c)=1.
Prove that if a > b then gcd(a, b) = gcd(b, a mod b).
Prove that if a > b then gcd(a, b) = gcd(b, a mod b).
Assume that gcd(a, m) = 1, gcd(a, n) = 1, and gcd(m, n) = 1. Assume...
Assume that gcd(a, m) = 1, gcd(a, n) = 1, and gcd(m, n) = 1. Assume that a has order s modulo m and order t modulo n. What is the order of a modulo mn? Prove that your answer is correct
Prove that for all non-zero integers a and b, gcd(a, b) = 1 if and only...
Prove that for all non-zero integers a and b, gcd(a, b) = 1 if and only if gcd(a, b^2 ) = 1
How can I prove that if a>b>0, gcd(a,b) = gcd(a-b,b)
How can I prove that if a>b>0, gcd(a,b) = gcd(a-b,b)
suppose p is a prime number and p2 divides ab and gcd(a,b)=1. Show p2 divides a...
suppose p is a prime number and p2 divides ab and gcd(a,b)=1. Show p2 divides a or p2 divides b.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT