Question

Solve the differential equation: y' = sqrt((y-x)/x) + 1 y(1) = 10

Solve the differential equation:

y' = sqrt((y-x)/x) + 1

y(1) = 10

Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve the following differential equation. Put your solution in explicit form. y'-y=-t/sqrt(y)
Solve the following differential equation. Put your solution in explicit form. y'-y=-t/sqrt(y)
solve the differential equation y'=y/x+3x^2+x
solve the differential equation y'=y/x+3x^2+x
solve the given differential equation by variation of parameters. y”+y=1/cos(x)
solve the given differential equation by variation of parameters. y”+y=1/cos(x)
1. Find the general solution of the first order linear differential equation: 2*x*dy/dx -y-3/sqrt(x)=0. sqrt() =...
1. Find the general solution of the first order linear differential equation: 2*x*dy/dx -y-3/sqrt(x)=0. sqrt() = square root of (). 2. Are there any transient terms in the general solution? Justify your answer.
solve differential equation ((x)2 - xy +(y)2)dx - xydy = 0 solve differential equation (x^2-xy+y^2)dx -...
solve differential equation ((x)2 - xy +(y)2)dx - xydy = 0 solve differential equation (x^2-xy+y^2)dx - xydy = 0
solve the differential equation y'' +y=(sin^2)x
solve the differential equation y'' +y=(sin^2)x
Solve the differential equation y'+(4/x) y=x^3 y^2
Solve the differential equation y'+(4/x) y=x^3 y^2
Solve the differential equation (1-y)dx-x^2y^2dy=0
Solve the differential equation (1-y)dx-x^2y^2dy=0
(x-y)dx + (y+x)dy =0 Solve the differential equation
(x-y)dx + (y+x)dy =0 Solve the differential equation
Solve the differential equation: d/dx*y(x) + y(x) = 3 y(x) = ?
Solve the differential equation: d/dx*y(x) + y(x) = 3 y(x) = ?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT