Hi I am trying some proofs and I am stuck on this one. It says to prove or give a counter example. For each real number p, there exist real numbers q and r such that qsin(r/5) =p.
Doubt in this then comment below.. i will help you..
.
Please thumbs up for this solution..thanks..
.
Note one thing that value of sin is in between -1 to 1 ...
So, here sin(r/5) = p/q ....
So we take q such that p/q lies between -1 and 1 ...
So, for p positive , we take q is greater than p
And for p negative , we take q is less than p ....
Such that above condition hold ...
That means sin(r/5) exist ... Therefore , value of r also exist ...
So for each p in real number .. there exist real numbers q and r such that qsin(r/5) = p ....
Get Answers For Free
Most questions answered within 1 hours.