We know that, for every subgroup H of Sn, either H is contained in An or exactly half of the elements of H are in An.
D6 is a subgroup of S6 in a natural way. We also have that the number of elements in D6 =12.
Note that the element (1 2 3 4 5 6), which corresponds to 60° rotation, is in D6. However, being a cycle of length 6 (even length) , it is an odd permutation, as
(1 2 3 4 5 6)= (1 6) (1 5) (1 4) (1 3) (1 2)
which is a product of odd number of transpositions.
Thus, exactly half of the elements of D6 are in A6, i.e,
the order of the group A6 intersection D6 = 12/2 = 6.
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