Question

Solve the ODE y"+3y'+2y=(e^-t)(sin2t) when y'(0)=y(0)=0

Solve the ODE
y"+3y'+2y=(e^-t)(sin2t) when y'(0)=y(0)=0
Math   Advanced-Math   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0) y(0)=0,y''(0)=0
Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0) y(0)=0,y''(0)=0
Use Laplace to solve y" + 2y' + 2y = e-t, y(0) = 0, y'(0) =...
Use Laplace to solve y" + 2y' + 2y = e-t, y(0) = 0, y'(0) = 1
Question : y''+6y'+9y=0,y(0)=2,y'(0)=1 , 4y''+12y'+9y=0,y(0)=2,y'(0)=2 y''-y'-2y=cosx , y''+3y'+2y=x^2 - e^2x , y''-3y'+2y=sinx  , y''-2y'-3y=3e^2x
Question : y''+6y'+9y=0,y(0)=2,y'(0)=1 , 4y''+12y'+9y=0,y(0)=2,y'(0)=2 y''-y'-2y=cosx , y''+3y'+2y=x^2 - e^2x , y''-3y'+2y=sinx  , y''-2y'-3y=3e^2x
Solve y'-3y=2e^t y(0)=e^3-e using Laplace transform.
Solve y'-3y=2e^t y(0)=e^3-e using Laplace transform.
y"-3y''''+2y= te^2t, y(0)=1, y''(0)=4 solve
y"-3y''''+2y= te^2t, y(0)=1, y''(0)=4 solve
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve...
Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1 Solve the IVP using the Eigenvalue method. x'=2x-3y+1 y'=x-2y+1 x(0)=0 y(0)=1
solve using the laplace transform y''-2y'+y=e^-t , y(0)=0 , y'(0)=1
solve using the laplace transform y''-2y'+y=e^-t , y(0)=0 , y'(0)=1
y^''-y^'-2y= e^t , y(0)=0 and y^'(0)=1 Solve by using laplace transform
y^''-y^'-2y= e^t , y(0)=0 and y^'(0)=1 Solve by using laplace transform
Please solve the listed initial value problem: y'' + 3y' + 2y = 1 - u(t...
Please solve the listed initial value problem: y'' + 3y' + 2y = 1 - u(t - 10); y(0) = 0, y'(0) = 0
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) = 1, y'(0) = 0.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT