A young person with no initial capital invests k dollars per year at an annual rate of return r. Assume that investments are made continuously and that the return is compounded continuously.
(a) Determine the sum S(t) accumulated at any time t.
(b) If r = 6.0%, determine k so that $1 million will be available for retirement in 43 years.
(c) If k=2500/year, determine the return rate r that
must be obtained to have $1 million available in 43
years.
(a) The differential equation for continuously compounding
investment is
dS/dt = rS + k
dS/dt - rS = k
u(t)*dS/dt - u(t)*rS = u(t)*k
du(t)/dt = -u(t) * r
(du(t)/dt) / u(t) = -r
d(ln|u(t)|)/dt = -r
ln|u(t)| = -rt + c
u(t) = ce^(-rt)
d[s * e^(-rt)]/dt = k * e^(-rt)
s * e^(-rt) = k * (int(e^(-rt))
s * e^(-rt) = (-k/r) * e^(-rt) + C
s = (-k/r) + C * (e^rt)
(s,t) = (0,0)
C = -k/r
s = (-k/r) + (k/r) * e ^ (rt)
s = (-k/r) + (k/r) * e ^ (rt)
Answer: s(t) = (k/r) * ((e^rt) - 1)
--------------------------------------…
b) r = 0.06
t = 43 years
s = 10^6
10^6 = (k/0.06) * (e^(2.58) - 1)
Answer: k = 4919.1867
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c) k = 200
s = 10^6
t = 43 years
10^6 = (2500/r) * ((e^43r) - 1)
400r = e^43r - 1
r= 0.08182
Answer: r = 8.18 %
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