For each of the following equations, find the general solution (perferably using imaginary numbers):
y′′ −2y′ −3y=3e2t;
y′′ +2y′ =3+sin(2t);
x2y′′ +7xy′ +5y=x;
x2y′′ +xy′ +4y=sin(lnx)+sin(2lnx);
y′′ +y=tcost.
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