Question

Solve the given initial-value problem. 5y'' + y' = −6x, y(0) = 0, y'(0) = −25...

Solve the given initial-value problem. 5y'' + y' = −6x, y(0) = 0, y'(0) = −25

The answer I got is 155-155e^(-1/5)x-3x^2-30x

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Answer #1

we first find auxilary equation then its roots to find yc.to find yp we use method of undetermined coefficients.to find constant we apply initial condition.in yp there is a constant term c but writing y(x) we can added this to constant term c1 in yc.so we get a constant c3=c+c1.

I think there is a problem in your answer.

My answer is

y(x)=-3x2+30x-275+275e(-x/5)

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