Question

y"-3y''''+2y= te^2t, y(0)=1, y''(0)=4

solve

Answer #1

Use
Laplace transform to solve IVP
2y”+2y’+y=2t , y(0)=1 , y’(0)=-1

Solve the IVP using the Eigenvalue method.
x'=2x-3y+1
y'=x-2y+1
x(0)=0
y(0)=1
x'=2x-3y+1
y'=x-2y+1
x(0)=0
y(0)=1
Solve
the IVP using the Eigenvalue method.
x'=2x-3y+1
y'=x-2y+1
x(0)=0
y(0)=1

Find a particular solution for:
y” - 3y’ + 2y = te-3t

Use
the Laplace transform to solve:
y’’ + 2y’ + y = e^(2t); y(0) = 0, y’(0) = 0.

Solve y''+3y'+2y=Delta(t-1)+t^13*Delta(t-0)
y(0)=0,y''(0)=0

Solve the ODE
y"+3y'+2y=(e^-t)(sin2t) when y'(0)=y(0)=0

Solve the given initial-value problem.
2y'' + 3y' −
2y = 10x2 −
4x − 15, y(0) = 0,
y'(0) = 0

solve y''-3y'+2y=0 using power series please

Solve the differential equation by variation of parameters. y''
+ 3y' + 2y = 1/(4+e^x)

y'-2y = 8sin(2t) , y(0) = -4
Use Laplace Transform

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