Question

Solve the differential equation y'+(4/x) y=x^3 y^2

Answer #1

solve the separable differential eq. y'=(y-3)(y+2)/(x-2)(x=4).
solve for y.

solve differential equation ((x)2 - xy +(y)2)dx - xydy
= 0
solve differential equation (x^2-xy+y^2)dx - xydy =
0

solve the differential equation
y'=y/x+3x^2+x

Consider the differential equation x′=[2 −2 4 −2], with x(0)=[1
1] Solve the differential equation wherex=[x(t)y(t)]
please write as neat as possible better if typed and explain
clearly with step by step work

Solve the differential equation:
d/dx*y(x) + y(x) = 3
y(x) = ?

solve differential equation
(x^2)y'' - xy' +y =2x

Solve the differential equation:
a) y'= t^2y^3 / t^3+6
b) y'= x(e^x^2 +2) / 6y^2 ; y(0) =1

Solve the differential equation (5x^4 y^2+ 2xe^y - 2x cos (x^2)) dx
+ (2x^5y + x^2 e^y) dy = 0.

Solve the differential equation : 4 x y y' = y2 + x2
with initial condition y(1)=1

4) Solve the following differential equation dy dx = y x + x
pls show me the steps

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