Question

ball weighing 1 pound is thrown vertically upward from a point 6 ft above the surface...

ball weighing 1 pound is thrown vertically upward from a point 6 ft above the surface of the earth with an initial velocity of 18 ft/sec. As it rises it is acted upon by air resistance that is numerically equal to (1/16)*v (in pounds) where v is the velocity (in feet per second).
How high will the ball rise?


NOTE: Before you attempt to answer, please take into consideration that this problem is for a Differential Equations class (NOT A PHYSICS CLASS) so please help me accordingly. Thank you! :)

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