Question

ball weighing 1 pound is thrown vertically upward from a point 6
ft above the surface of the earth with an initial velocity of 18
ft/sec. As it rises it is acted upon by air resistance that is
numerically equal to (1/16)*v (in pounds) where v is the velocity
(in feet per second).

How high will the ball rise?

NOTE: Before you attempt to answer, please take into consideration
that this problem is for a Differential Equations class (NOT A
PHYSICS CLASS) so please help me accordingly. Thank you! :)

Answer #1

A ball is thrown vertically upward from the 40-ft level in an
elevator shaft with an initial velocity (straight up) of 50 ft/sec.
At the same instant, far below, an open-platform elevator passes
the 10-ft level in the elevator shaft, moving upward with a
constant velocity of 5 ft/sec. Determine (a) when and where the
ball will hit the elevator, (b) the relative velocity of the ball
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A ball is thrown vertically upward from a height of 5 ft with an
initial velocity of 83 ft/s. The distance s (in feet) of the ball
from the ground after t seconds is s = s(t) = 5 + 83t − 16t^2. (a)
What is the velocity v, in feet per second, of the ball after 2
seconds?
(b) When, in seconds, will the ball reach its maximum height?
(Round your answer to one decimal place.)
(c) What is...

A
ball is thrown directly upward from a height of 3 ft with an
initial velocity of 20 ft/sec. the function s(t) = -16t^2+20t+3
gives the height of the ball, in feet, t seconds after it has been
thrown. Determine the time at which the ball reaches its maximum
height and find the maximum height.

if a ball is thrown vertically upward with a velocity of 95
ft/s, then its height after t seconds is
s=95t-19t^2
A. what is maximum height reached by the ball?
B. what is the velocity of the ball if its 114 ft above the
ground on the way up?
C. what is the velocity of the ball when it is 114 above the
ground on its way down?

17) A ball is thrown vertically upward from ground level with an
initial velocity of 96 feet per second. Use ?(?) = −32 ??⁄ 2.
a) How long will it take it to rise to its maximum height? b)
What is the maximum height?

An object is thrown vertically upward from a platform 80 feet
above the ground with a velocity of 64 feet per second. Given the
fact that the acceleration due to gravity is approximately -32
ft/sec/sec,
a) use antidifferentiation to determine the ‘velocity’, v(t), and
‘position above the ground’, s(t), functions; use these functions
to determine: b) when the object reaches its highest point; c) what
the highest point above the ground is; d) when it hits the ground;
e) the...

if a baseball is thrown vertically upward with an initial
velocity of 128 ft/sec, the ball’s height after t seconds is
s(t)=128t-16t^2
A. Find the baseball's velocity and acceleration at time
t.
B. How long does it take the baseball to reach its highest
point?
C. How high does the baseball go?
D. What is the velocity of the ball when it is 112 ft above
the ground on the wh down?
E. What is the speed of the ball...

A
ball is thrown upward from a height of 3m at an initial speed of 45
m / sec. Acceleration resulting from gravity is -9.8 m/sec^2.
Neglecting air resistance, solve for the velocity, v(t), and the
height, h(t), of the ball t seconds after it is thrown and before
it hits the ground.

A ball is thrown directly upward from the edge of a
rock and travels such that after t seconds its height in feet above
the ground is given by the equation s(t) =-2.5t^2+10t+2
1.Find the equation that represents the instant
velocity v(t) of the ball on t time.
2.When does the ball has zero velocity?
3. What is the maximum height that the ball
reaches?
4. When does the ball touches the surface of the
Earth?
5. build the graph...

A ball with mass 1/9.8 kg is thrown upward with initial velocity
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of air resistance (drag force) is (v^2)/1225. Find the maximum
height above the ground that the ball reaches. (Hint: ﬁnd the
velocity v(t) ﬁrst, then ﬁnd the height x(t).)

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