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The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^,...

The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→=(19.0m)i^+(44.0m)j^ locates the particle, which then has the velocity vector v→=(5.40m/s)i^+(1.70m/s)j^. At t = 4.10 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?

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