Question

(1 point) A tank contains 1520 L of pure water. A solution that contains 0.04 kg of sugar per liter enters the tank at the rate 8 L/min. The solution is mixed and drains from the tank at the same rate.

(a) How much sugar is in the tank at the beginning? y(0)=

(b)Find the amount of sugar (in kg) after t minutes. S(t)=

(c)Find the amount of the sugar after 90 minutes. S(90)=

Answer #1

A tank contains 2100 L of pure water. Solution that contains
0.05 kg of sugar per liter enters the tank at the rate 4 L/min, and
is thoroughly mixed into it. The new solution drains out of the
tank at the same rate.
(b) Find the amount of sugar after t minutes.
y(t)=

A tank contains 1280 L of pure water. Solution that contains
0.02 kg of sugar per liter enters the tank at the rate 3L/min, and
is thoroughly mixed into it. The new solution drains out of the
tank at the same rate.
(a) How much sugar is in the tank at the beginning?
(b) Find the amount of sugar after t minutes.
y(t)=
As t becomes large, what value is y(t)
approaching ? In other words, calculate the following limit....

(1 point) A tank contains 2780 L of pure water. Solution that
contains 0.01 kg of sugar per liter enters the tank at the rate 4
L/min, and is thoroughly mixed into it. The new solution drains out
of the tank at the same rate.
(a) How much sugar is in the tank at the begining?
y(0)= (kg)
(b) Find the amount of sugar after t minutes.
y(t)= (kg)
(c) As t becomes large, what value is y(t)y(t) approaching ?...

A tank contains 2100 L of pure water. Solution that contains
0.05 kg of sugar per liter enters the tank at the rate 44 L/min,
and is thoroughly mixed into it. The new solution drains out of the
tank at the same rate.
(a) How much sugar is in the tank at the begining?
y(0)=
(b) Find the amount of sugar after t minutes.
y(t)=
(c) As t becomes large, what value is y(t) approaching ? In
other words, calculate...

A tank contains 1000 L of pure water. Brine that contains 0.05
kg of salt per liter of water enters the tank at a rate of 5 L/min.
Brine that contains 0.04 kg of salt per liter of water enters the
tank at a rate of 10 L/min. The solution is kept thoroughly mixed
and drains from the tank at a rate of 15 L/min.
(a) How much salt is in the tank after t minutes?
y=

A tank contains 1000 L of pure water. Brine that contains 0.05
kg of salt per liter of water enters the tank at a rate of 5 L/min.
Brine that contains 0.04 kg of salt per liter of water enters the
tank at a rate of 10 L/min. The solution is kept thoroughly mixed
and drains from the tank at a rate of 15 L/min.
(a) How much salt is in the tank after t minutes?
(b) How much salt...

A tank contains 90 kg of salt and 2000 L of water: Pure water
enters a tank at the rate 8 L/min. The solution is mixed and drains
from the tank at the rate 8 L/min. What is the amount of salt in
the tank initially? Find the amount f salt in the tank after 4.5
hours. Find the concentration of salt in the solution in the tank
as the time approaches infinity. (Assume your tank is large enough
to...

A tank contains 100 kg of salt and 1000 L of water. Pure water
enters a tank at the rate 12 L/min. The solution is mixed and
drains from the tank at the rate 6 L/min.
(a) What is the amount of salt in the tank initially?
(b) Find the amount of salt in the tank after 4.5 hours.

A tank contains 80 kg of salt and 1000 L of water. Pure water
enters a tank at the rate 6 L/min. The solution is mixed and drains
from the tank at the rate 3 L/min. Find the amount of salt in the
tank after 2 hours. What is the concentration of salt in the
solution in the tank as time approaches infinity?

A tank contains 1000 L of brine (saltwater) with 15 kg of
dissolved salt. Pure water enters the tank at a rate of 10 L/min.
The solution is kept thoroughly mixed and drains from the tank at
the same rate. How much salt is in the tank after t minutes?

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