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The general solution of the equation y′′+6y′+13y=0 is y=c1e-3xcos(2x)+c2e−3xsin(2x)   Find values of c1 and c2 so...

The general solution of the equation y′′+6y′+13y=0 is y=c1e-3xcos(2x)+c2e−3xsin(2x)  

Find values of c1 and c2 so that y(0)=1 and y′(0)=−9.

c1=?

c2=?

Plug these values into the general solution to obtain the unique solution.

y=?

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