Question

What is the correct meaning of the logical expression p→q∨r∧s ?

((p→q)∨r)∧s

p→((q∨r)∧s)

(p→(q∨r))∧s

p→(q∨(r∧s))

Answer 1

Correct answer is Option (D)

Explanation:

The operators precedence of   is

which means , where "logical and" is greater than "logical or" greater than "implication"

So first we evaluate r and s, then we calculate q or (r and s) and atlast we calculates p implies (q or (r and s))

So the answer is

Mention in comments if any mistakes are found. Thank you.