Question

What is the correct meaning of the logical expression p→q∨r∧s ? ((p→q)∨r)∧s p→((q∨r)∧s) (p→(q∨r))∧s p→(q∨(r∧s))


What is the correct meaning of the logical expression p→q∨r∧s ?

((p→q)∨r)∧s
p→((q∨r)∧s)
(p→(q∨r))∧s
p→(q∨(r∧s))
Math   Advanced-Math   
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Homework Answers

Answer #1

Correct answer is Option (D)

Explanation:

The operators precedence of   is

which means , where "logical and" is greater than "logical or" greater than "implication"

So first we evaluate r and s, then we calculate q or (r and s) and atlast we calculates p implies (q or (r and s))

So the answer is

Mention in comments if any mistakes are found. Thank you.

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