Question

1) Consider the following differential equation to be solved by variation of parameters.

y'' + y = sec(θ) tan(θ)

Find the complementary function of the differential equation.

y_{c}(θ) =

Find the general solution of the differential equation.

y(θ) =

2) Solve the given differential equation by undetermined coefficients.

y'' + 5y' + 4y = 8

y(x) =

Answer #1

Find a solution to y^''-4y^'-5y=2e^2t using variation of
parameters. Find the solution to the differential equation in
problem 6, this time using the method of undetermined
coefficients.

solve differential equation by variation of parameters
y''+y=sec(theta) tan(theta)

3. Find the general solution if the given differential equation
by using the variation of parameters method. y''' + y'= 2 tan x, −
π /2 < x < π/2

Solve the differential equation by variation of parameters.
5y'' − 10y' + 10y = ex sec(x)
y(x) = ______.

Solve the following differential equation by variation of
parameters. Fully evaluate all integrals.
y′′+9y=sec(3x).
a. Find the most general solution to the associated homogeneous
differential equation. Use c1 and c2 in your
answer to denote arbitrary constants, and enter them as c1 and
c2.
b. Find a particular solution to the nonhomogeneous differential
equation y′′+9y=sec(3x).
c. Find the most general solution to the original nonhomogeneous
differential equation. Use c1 and c2 in your
answer to denote arbitrary constants.

Solve Differential equation by variation of parameters method.
y"-5y'+6y=e^x

differential equations!
find the Differential Equation General Solve by using
variation of parameters method...
y''' - 3y'' +3y' - y =12e^x

Use variation of parameters to solve the following differential
equations
y''+4y'+4y=e^(t)tan^-1(t)

solve differential equation by variation of parameters
y''+y=sec(theta) tan(theta)
simple and clear answer no need for writing words just do the
math

Solve the differential equation by variation of parameters.
y'' + 4y = sin(2x)

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