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Fix a ∈ C and b ∈ R. Show (prove) that the equation |z^2|+Re(az)+b = 0...

Fix a ∈ C and b ∈ R. Show (prove) that the equation |z^2|+Re(az)+b = 0 has a solution if and only if |a2| ≥ 4b. When solutions exist show the solution set is a circle.

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