We are given a sequence of numbers: 1, 3, 5, 7, 9, . . . and want to prove that the closed formula for the sequence is an = 2n – 1.
Critical Thinking
Now if we could prove that if it is true for ax-1 then it is true for ax, we could conclude that it is true for any an. This is the Principle of Mathematical Induction.
We will assume that the closed formula is correct and apply it to a(m-1) by replacing “n” in the closed formula (an = 2n – 1) with “m – 1” we get
am =
(2(______) -1) + 2
am = ((2m – 2) – 1)+
2 by distributing
the factor 2 over (m – 1)
am = (2m – 2 + 2) – 1)
by commutative and associative properties
am = _____________
by simplifying through
arithmetic.
We have shown that if the closed formula is true the
base case and that if it is true for the (m
-1)th term in the sequence, then it is true for the
mth term.
This concept of proof by induction may take some time to “wrap you head around”. We first showed that it was true for the base case (a1). We then showed at if it is true for the some term in the sequence, then it is true for the next term, and if it is true for the next term would then be true for the next, and the next, and the next, …
Application
Prove by mathematical induction:
am = am–1 + 4
Starting out with the recursive formula expressed using
m
You must complete the proof. You can begin by expressing the
term
am–1 using the closed formula and substituting “m – 1”
for “n”.
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