Question

Find the vertex, focus and directrix of the following parabola and sketch its graph y+12x-2x^2=16

Find the vertex, focus and directrix of the following parabola and sketch its graph

y+12x-2x^2=16

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1) Find the equation of the line that psses through the vertex if the parabola f(x)=2x^2-12x+19...
1) Find the equation of the line that psses through the vertex if the parabola f(x)=2x^2-12x+19 and that crosses the x-axis at x=5 2) Find the equation of the line that passes through the certex of the parabala f(x)=3x^2-12x+17 and has y-intercept of (0,10)
For the following​ problem, do not include a graph. ​(a) For the parabola y=−2x^2+9x+1​, find the...
For the following​ problem, do not include a graph. ​(a) For the parabola y=−2x^2+9x+1​, find the vertex. ​(b) Does the vertex correspond to the highest point or the lowest point on the​ graph?
the parabola y^2=12x is shifted up 2 units and left 3 units. find an equation for...
the parabola y^2=12x is shifted up 2 units and left 3 units. find an equation for the new parabola, and find the new vertex, focus, and directions
Find parabola equation? Find equation of parabola: Focus: (9,0), directrix x=-9
Find parabola equation? Find equation of parabola: Focus: (9,0), directrix x=-9
1. Determine the equation of the parabola with focus (−3,5) and directrix y=1 2. Determine the...
1. Determine the equation of the parabola with focus (−3,5) and directrix y=1 2. Determine the equation of the parabola with focus (5/2, −4) and directrix x=7/2 3. Determine the equation of the ellipse using the information given. Endpoints of major axis at (4,0), (−4,0) and foci located at (2,0), (−2,0) 4. Determine the equation of the ellipse using the information given. Endpoints of major axis at (0,5), (0,−5) and foci located at (3,0), (−3,0)
the focus of a parabola opening upwards is at the point (-1,7) the point (11,12) is...
the focus of a parabola opening upwards is at the point (-1,7) the point (11,12) is on the graph of the parabola 1.) what is the directrix 2.) what is the vertex of the parabola 3.) write the equation for the parabola
Find an equation of a parabola satisfying the given conditions Focus (4, 1) and directrix x...
Find an equation of a parabola satisfying the given conditions Focus (4, 1) and directrix x = -2.
. Find the second degree equation if the vertex of the parabola is (4, -2) and...
. Find the second degree equation if the vertex of the parabola is (4, -2) and one point on the parabola is (1, 5). Sketch y = ?−4 /(?+1)(?−2) Tell me ALL your considerations! If there is a horizontal asymptote, does your graph cross it? Where? Show me your work to justify your answer.
1)Find the vertex and the x-intercepts (if any) of the parabola. (If an answer does not...
1)Find the vertex and the x-intercepts (if any) of the parabola. (If an answer does not exist, enter DNE.) f(x) = 3x2 − 5x − 2 vertex (x, y) =    x-intercept   (x, y) =        (smaller x-value) x-intercept   (x, y) =        (larger x-value) Sketch the parabola. 2)Find the vertex and the x-intercepts (if any) of the parabola. (If an answer does not exist, enter DNE.) f(x) = x2 + 4x + 4 vertex (x, y) =    x-intercept...
graph the parabola y=-x^2 -4x +5. list vertex, aos, and y,x intercepts
graph the parabola y=-x^2 -4x +5. list vertex, aos, and y,x intercepts
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT