Question

Solve y''+3y' -10y=e^{2x}+e^{5x} + 10 by
undetermined coefficients.

Answer #1

use the method of undetermined coefficients to solve the
differential equation)
y'' + 2y' - 3y = (x2 + x + 1) + e-3x

Use the method of undetermined coefficients to solve:
y''+3y'-4y=(e^t)+2(e^-(5t))

Can you solve this Differential Ecuation with the method of
undetermined coefficients:
y"-3y'-4y=xe2x-cosx (superposition principle)

y''+y'=3x
solve by method of undetermined coefficients

y^'''-2^''+10y^'=3xe^x
Solve by using Undetermined Coefficient method

What particular solution would use to solve the following NHDE
using Undetermined Coefficients? DO NOT SOLVE THE
DE
y''-10y'+5y=9t3e2t+cost+t2sint

Use the method of undetermined coefficients to solve
y′′−3y′+2y=30sin(x)+ 12e−x+ 2
Could you go step by step and explain everything please? Thank
you in advance

Using undetermined coefficients, what is the form of yp in the
differential equation y''-3y'+2y = x^2 + xsin(x) - e^x. Do not
solve for yp, just find the general form.

find the general solution by undetermined coefficients method.
y′′-3y′+2y=-9x^2+6x

Solve y"-4y=12x2 +6+4e2x By: Undetermined
Coefficients

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