Proposition 16.4 Let S be a non–empty finite set.
(a) There is a unique n 2 N1 such that there is a 1–1
correspondence from {1, 2,...,n} to S.
We write |S| = n. Also, we write |;| = 0.
(b) If B is a set and f : B ! S is a 1–1 correspondence, then B is
finite and |B| = |S|.
(c) If T is a proper subset of S, then T is finite and |T| <
|S|.
Prove part b.
we have to prove part (b)
is a one to one correspondence
we know the definition of one to one map if or
so image of i.e then is finite
and given set is finite , and there is a one to one correspondence between to finite set ,
hence
Get Answers For Free
Most questions answered within 1 hours.