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Consider m=24, i.e., Xn+1 =(aXn) mod 24. (Hint: This is a common case for a linear...

Consider m=24, i.e., Xn+1 =(aXn) mod 24. (Hint: This is a common case for a linear congruential algorithm when m is a power of 2.)

What restrictions are required on the seed?

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Answer #1

The highest order will be

Checking through the possibilities to find an element of order 8, we note that

means

That is,

And

Thus, we have no elements of order 4 and so there are no elements of order 8. We will have a maximum order of 2 and one such element providing an element of order 2 is

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