Question

Question1:

You have these values for x and f(x):

x

1.20

1.25

1.30

1.35

1.40

1.45

1.50

f(x)

0.1823

0.2231

0.2624

0.3001

0.3365

0.3716

0.4055

Find the f(x) of (1.32) from a linear interpolation of direct method

Find the f(x) of (1.32) from a linear interpolation of Newton method

Find the f(x) of (1.32) from a linear interpolation of splines method

Compare the result in (a), (b) and (c) with the exact solution of f(1.32)=(0.27766)

Question2:

When Splines methods are used, and where the connectivity between points are improved ?

Answer 1