if f is holomorphic on D[2,7] and takes only pure imaginary values, must f be constant? Prove or disprove
Answer:
Here f(z) is holomorphic. let f = u + iv
Where u = u(x, y), v = v(x, y)
Now given that f(z) takes only purely imaginary value then u = 0,
so f = +iv
By Cauchy Riemann theorem we have
Now u = 0 ,
~
v = constant = c (let)
So f(z) is a constant function.
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